Compute the sample median. The function basically wraps the function
quantileX(), which offers the option to define weights.
For
grouped data the median can be estimated by linear interpolation within the
class containing the median, which is implemented in the interface for
Freq-objects.
Usage
medianX(x, ...)
# Default S3 method
medianX(x, weights = NULL, na.rm = FALSE, ...)
# S3 method for class 'factor'
medianX(x, na.rm = FALSE, ...)
# S3 method for class 'Freq'
medianX(x, breaks, ...)Arguments
- x
an object for which a method has been defined, or a numeric vector containing the values whose median is to be computed
- ...
further arguments passed to or from other methods
- weights
a numerical vector of weights the same length as
xgiving the weights to use for elements ofx- na.rm
a logical value indicating whether
NAvalues should be stripped before the computation proceeds- breaks
breaks for calculating the mean for classified data as composed by
freq()
Value
the default method returns a length-one object of the same type as
x, except when x is integer of even length, when the result
will be double.
If there are no values or if na.rm = FALSE and there are NA
values the result is NA of the same type as x (or more
generally the result of x[FALSE][NA]).
Details
This is a generic function for which methods can be written. However, the
default method makes use of is.na, sort and mean from
package base all of which are generic, and so the default method will
work for most classes (e.g., "[Date]") for which a median is a
reasonable concept.
Calculating the median for ordered factors is not implemented in standard R, as it's not well defined (it is not clear what to do if the median sits between two levels in factors of even length). This function returns the high median and prints a warning if the low median would be different (which is supposed to be a rare event). There's a vivid discussion between experts going on whether this should be defined or not. We'll wait for definitive results and enjoy the function's comfort so far...
Note
There are alternative approaches for calculating weighted median
(e.g. matrixstats::weightedMedian).
References
Becker, R. A., Chambers, J. M. and Wilks, A. R. (1988) The New S Language. Wadsworth & Brooks/Cole.
See also
quantile() for general quantiles,
Maechler on R-help mailing list, 2003-Nov
StackOverflow discussion on median
Other location:
gmean(),
hmean(),
hodgesLehmann(),
huberM(),
meanX(),
modeX(),
tukeyBiweight()
Examples
medianX(1:4) # = 2.5 [even number]
#> [1] 2.5
medianX(c(1:3, 100, 1000)) # = 3 [odd, robust]
#> [1] 3
# Approximation for classified data
breaks <- seq(10,70, 10)
medianX(
freq(cut(Pizza$temperature, breaks=breaks)),
breaks=breaks)
#> [1] 49.91404
# compared to
medianX(Pizza$temperature)
#> [1] NA
# starting from a classified table
# from to income
# 0 4000 20
# 4000 6000 42
# 6000 8000 31
# 8000 10000 12
# freq(as.table(c(20,42,31,12)))
# level freq perc cumfreq cumperc
# 1 A 20 19.0% 20 19.0%
# 2 B 42 40.0% 62 59.0%
# 3 C 31 29.5% 93 88.6%
# 4 D 12 11.4% 105 100.0%
medianX(freq(as.table(c(20,42,31,12))), breaks=c(0,4000,6000,8000,10000))
#> [1] 5547.619
# use weights
x <- sample(20, 30, replace = TRUE)
z <- as.numeric(names(w <- table(x)))
(m1 <- medianX(z, weights=w))
#> [1] 8.5
(m2 <- medianX(x))
#> [1] 8.5
stopifnot(identical(m1, m2))
